4xN
Optimal Domination Numbers
Solutions and Proofs
Part 1 of 3
4xN Optimal Domination Numbers
D(4,N) = the domination number for a board with 4 rows and N columns.
D(4,1) = 4
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D(4,2) = 4
D(4,3) = 4
D(4,4) = 4
D(4,5) = 4
D(4,6) = 4
D(4,7) = 6
------------
D(4,N+6) = D(4,N) + 4 for N >= 2
Part 2 of 3
4xN Sufficiency Proofs
Sufficiency is proved by showing a feasible solution
using the domination number of knights.
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D(4,1) <= 4
x
x
x
x
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Extendable solution by repeating the first six columns
D(4,2) <= 4 D(4,6k+2) <= 4k+4
- - - - - - - - - -
x x - - x x - - x x
x x - - x x - - x x
- - - - - - - - - -
\---------/
repeats
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Extendable solution by repeating the first six columns
D(4,3) <= 4 D(4,6k+3) <= 4k+4
- - - - - - - - - - - -
- x x - - x x - - - x x
- x x - - x x - - - x x
- - - - - - - - - - - -
\---------/
repeats
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Extendable solution by repeating the first six columns
D(4,4) <= 4 D(4,6k+4) <= 4k+4
- - - - - - - - - - - - - -
- - x x - - x x - - - - x x
- - x x - - x x - - - - x x
- - - - - - - - - - - - - -
\---------/
repeats
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Extendable solution by repeating the first six columns
D(4,5) <= 4 D(4,6k+5) <= 4k+4
- - - - - - - - - - - - - - - -
- - x x - - - x x - - - - x x -
- - x x - - - x x - - - - x x -
- - - - - - - - - - - - - - - -
\---------/
repeats
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Extendable solution by repeating the first six columns
D(4,6) <= 4 D(4,6k) <= 4k
- - - - - - - - - - - - - - - - - -
- - x x - - - - x x - - - - x x - -
- - x x - - - - x x - - - - x x - -
- - - - - - - - - - - - - - - - - -
\---------/
repeats
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Extendable solution by repeating the first six columns
D(4,7) <= 6 D(4,6k+1) <= 4k+2
- - - - - - - - - - - - - - - - - - - -
- - x x x - - - - x x - - - - x x x - -
- - x x x - - - - x x - - - - x x x - -
- - - - - - - - - - - - - - - - - - - -
\---------/
repeats
Part 3 of 3
4xN Necessity Proofs
Necessity is proved by showing that
at least the domination number of knights is required
to cover a subset of the board.
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D(4,1) >= 4
o
o Since no square can be attacked,
o all squares must be covered by occupying them.
o
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D(4,2) >= 4
o o
o o 2x4 block requires 4 knights.
o o
o o
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D(4,3) >= 4
o o -
o o - 2x4 block requires 4 knights.
o o -
o o -
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D(4,4) >= 4
o o - -
o o - - 2x4 block requires 4 knights.
o o - -
o o - -
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D(4,5) >= 4
o o - - -
o o - - - 2x4 block requires 4 knights.
o o - - -
o o - - -
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Extendable optimality proof by repeating the first six columns.
D(4,6k) >= 4k
o o - - - -
o o - - - - Each repeatable 2x4 block requires a separate 4 knights.
o o - - - -
o o - - - -
\---------/
repeats
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Extendable optimality proof by repeating the first six columns.
D(4,6k+1) >= 4k+2
o o - - - - a Each repeatable 2x4 block requires a separate 4 knights.
o o - - - - - a-square and b-square each require a separate knight.
o o - - - - - Total is 4 times number of 2x4 blocks plus 2.
o o - - - - b
\---------/
repeats
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Extendable optimality proof by repeating the first six columns.
D(4,6k+2) >= 4k+4
o o - - - - a a Each repeatable 2x4 block requires a separate 4 knights.
o o - - - - a a The right-hand 2x4 block requires an extra 4 knights.
o o - - - - a a Total is 4 times number of 2x4 blocks plus 4.
o o - - - - a a
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repeats
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Extendable optimality proof by repeating the first six columns.
D(4,6k+3) >= 4k+4
o o - - - - a a - Same proof as D(4,6k+2).
o o - - - - a a -
o o - - - - a a -
o o - - - - a a -
\---------/
repeats
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Extendable optimality proof by repeating the first six columns.
D(4,6k+4) >= 4k+4
o o - - - - a a - - Same proof as D(4,6k+2).
o o - - - - a a - -
o o - - - - a a - -
o o - - - - a a - -
\---------/
repeats
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Extendable optimality proof by repeating the first six columns.
D(4,6k+5) >= 4k+4
o o - - - - a a - - - Same proof as D(4,6k+2).
o o - - - - a a - - -
o o - - - - a a - - -
o o - - - - a a - - -
\---------/
repeats
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