4xN
Optimal Domination Numbers
Solutions and Proofs

Part 1 of 3 4xN Optimal Domination Numbers
D(4,N) = the domination number for a board with 4 rows and N columns. D(4,1) = 4 ------------ D(4,2) = 4 D(4,3) = 4 D(4,4) = 4 D(4,5) = 4 D(4,6) = 4 D(4,7) = 6 ------------ D(4,N+6) = D(4,N) + 4 for N >= 2
Part 2 of 3 4xN Sufficiency Proofs
Sufficiency is proved by showing a feasible solution using the domination number of knights. ________________________________________________________ D(4,1) <= 4 x x x x ________________________________________________________ Extendable solution by repeating the first six columns D(4,2) <= 4 D(4,6k+2) <= 4k+4 - - - - - - - - - - x x - - x x - - x x x x - - x x - - x x - - - - - - - - - - \---------/ repeats ________________________________________________________ Extendable solution by repeating the first six columns D(4,3) <= 4 D(4,6k+3) <= 4k+4 - - - - - - - - - - - - - x x - - x x - - - x x - x x - - x x - - - x x - - - - - - - - - - - - \---------/ repeats ________________________________________________________ Extendable solution by repeating the first six columns D(4,4) <= 4 D(4,6k+4) <= 4k+4 - - - - - - - - - - - - - - - - x x - - x x - - - - x x - - x x - - x x - - - - x x - - - - - - - - - - - - - - \---------/ repeats ________________________________________________________ Extendable solution by repeating the first six columns D(4,5) <= 4 D(4,6k+5) <= 4k+4 - - - - - - - - - - - - - - - - - - x x - - - x x - - - - x x - - - x x - - - x x - - - - x x - - - - - - - - - - - - - - - - - \---------/ repeats ________________________________________________________ Extendable solution by repeating the first six columns D(4,6) <= 4 D(4,6k) <= 4k - - - - - - - - - - - - - - - - - - - - x x - - - - x x - - - - x x - - - - x x - - - - x x - - - - x x - - - - - - - - - - - - - - - - - - - - \---------/ repeats ________________________________________________________ Extendable solution by repeating the first six columns D(4,7) <= 6 D(4,6k+1) <= 4k+2 - - - - - - - - - - - - - - - - - - - - - - x x x - - - - x x - - - - x x x - - - - x x x - - - - x x - - - - x x x - - - - - - - - - - - - - - - - - - - - - - \---------/ repeats
Part 3 of 3 4xN Necessity Proofs
Necessity is proved by showing that at least the domination number of knights is required to cover a subset of the board. ________________________________________________________ D(4,1) >= 4 o o Since no square can be attacked, o all squares must be covered by occupying them. o ________________________________________________________ D(4,2) >= 4 o o o o 2x4 block requires 4 knights. o o o o ________________________________________________________ D(4,3) >= 4 o o - o o - 2x4 block requires 4 knights. o o - o o - ________________________________________________________ D(4,4) >= 4 o o - - o o - - 2x4 block requires 4 knights. o o - - o o - - ________________________________________________________ D(4,5) >= 4 o o - - - o o - - - 2x4 block requires 4 knights. o o - - - o o - - - ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k) >= 4k o o - - - - o o - - - - Each repeatable 2x4 block requires a separate 4 knights. o o - - - - o o - - - - \---------/ repeats ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k+1) >= 4k+2 o o - - - - a Each repeatable 2x4 block requires a separate 4 knights. o o - - - - - a-square and b-square each require a separate knight. o o - - - - - Total is 4 times number of 2x4 blocks plus 2. o o - - - - b \---------/ repeats ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k+2) >= 4k+4 o o - - - - a a Each repeatable 2x4 block requires a separate 4 knights. o o - - - - a a The right-hand 2x4 block requires an extra 4 knights. o o - - - - a a Total is 4 times number of 2x4 blocks plus 4. o o - - - - a a \---------/ repeats ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k+3) >= 4k+4 o o - - - - a a - Same proof as D(4,6k+2). o o - - - - a a - o o - - - - a a - o o - - - - a a - \---------/ repeats ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k+4) >= 4k+4 o o - - - - a a - - Same proof as D(4,6k+2). o o - - - - a a - - o o - - - - a a - - o o - - - - a a - - \---------/ repeats ________________________________________________________ Extendable optimality proof by repeating the first six columns. D(4,6k+5) >= 4k+4 o o - - - - a a - - - Same proof as D(4,6k+2). o o - - - - a a - - - o o - - - - a a - - - o o - - - - a a - - - \---------/ repeats ________________________________________________________